can a function return more than one value?

Answer 1

Yes - have your function return a struct. Or return the values via reference parameters.

struct A {
   int x, y;
   A( int a, int y ) : x(x), y(y) {}
};

A myfun() {
   return A( 0, 42 );    // return  two values
}

or:

void myfun( int & a, int & b ) {
   a = 0;
   b = 42;
}

Answer 2

No, but you can return a pair or boost::tuple which can contain multiple values.

In addition, you can use references to return multiple values like this:

void MyFunction(int a, int b, int& sum, int& difference);

You would call this function like this:

int result_sum;
int result_difference;
MyFunction(1, 2, result_sum, result_difference);

As Hogan points out, technically this isn't returning multiple variables, however it is a good substitute.

Answer 3

A function can return values in the specified ways:

• Via return value of any type
• Via a pointer
• Via a reference
• Via setting a global variable (highly not recommended)

If you need a self contained return value, you would typically wrap the types you need in a struct and return an object of that struct by value. If you want to avoid keeping a local copy you would pass in a reference parameter to be modified.

Answer 4

In the boost::tuple library, there's a function called tie that simplifies the process of getting information out of a returned tuple. If you had a function that returned a tuple of two doubles and wanted to load those into two local variables x and y, you could assign your function's return value to boost::tie(x, y).

Example:

#include <math.h>
#include <iostream>
#include <boost/tuple/tuple.hpp>

const double PI = 3.14159265;

boost::tuple<double, double> polar_to_rectangular(double radius, double angle)
{
    return boost::make_tuple(radius * cos(angle), radius * sin(angle));
}

int main()
{
    double x;
    double y;

    boost::tie(x, y) = polar_to_rectangular(4, (45 * PI) / 180);
    std::cout << "x == " << x << ", y == " << y << std::endl;

    return 0;
}

Answer 5

main()
{
int a=10,b=20;
int *c;
c=aa(a,b);
printf("%d %d",*c,*c+1);
}
void aa(int a,int b)
{
int c1[2];
c1[0]=b+a;
c1[1]=a-b;
return(c1);
}

here, the address of c1 will be return. so it will store in main c cariable. we can retrive both variable via pointer,

Answer 6

use structure and return multiple value with different data type.

Answer 7

include

include

include

typedef struct { int a; int b; }Mystruct;

Mystruct myfun();

int main() { char name[30]; Mystruct ms2; ms2 = myfun(); printf("val1: %d val2: %d",ms2.a,ms2.b); return 0; }

Mystruct myfun() { int a,b; Mystruct ms;

a = 10;
b = 20;
ms.a=a;
ms.b=b;

return(ms);

}