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10179

answers:

2

Problem: I have an integer; this integer needs to be converted to a stl::string type.

In the past, I've used stringstream to do a conversion, and that's just kind of cumbersome. I know the C way is to do a sprintf, but I'd much rather do a C++ method that is typesafe(er).

Is there a better way to do this?

Here is the stringstream approach I have used in the past:

std::string intToString(int i)
{
    std::stringstream ss;
    std::string s;
    ss << i;
    s = ss.str();

    return s;
}

Of course, this could be rewritten as so:

template<class T>
std::string t_to_string(T i)
{
    std::stringstream ss;
    std::string s;
    ss << i;
    s = ss.str();

    return s;
}

However, I have the notion that this is a fairly 'heavy-weight' implementation.

Zan noted that the invocation is pretty nice, however:

std::string s = t_to_string(my_integer);

At any rate, a nicer way would be... nice.

Related:

Alternative to itoa() for converting integer to string C++?

+7  A: 

Not really, in the standard. Some implementations have a nonstandard itoa() function, and you could look up Boost's lexical_cast, but if you stick to the standard it's pretty much a choice between stringstream and sprintf() (snprintf() if you've got it).

David Thornley
+11  A: 

Like mentioned earlier, I'd recommend boost lexical_cast. Not only does it have a fairly nice syntax:

std::string s = boost::lexical_cast<std::string>(i);

it also provides some safety:

try{
  std::string s = boost::lexical_cast<std::string>(i);
}catch(boost::bad_lexical_cast &){
 ...
}
Mic