I have an Exception chain in which method1
throws an Exception to method2
which throws the Exception on to main
. For some reason, the compiler forces me to deal with the error in method2
and marks it as an error if I don't, indicating that it's a checked Exception. But when the same Exception
is thrown further down the line to main
, the compiler allows me to ignore it and doesn't display any errors.
The original Exception in method1
is a ParseException
, which is checked. But the method has a generic throws Exception
clause in the header, and the same object is thrown to method2, which has an identical throws Exception
clause. When and how does this Exception lose the status of being checked / caught by the compiler?
Edited to clarify:
public void method1() throws Exception{
// code that may generate ParseException
}
public void method2() throws Exception{
method1(); //compiler error (if the throws clause is left out)
}
public static void main(String[] args){
method2(); //ignored by compiler, even though the exception isn't caught or thrown or handled at all
}
Edit:
Sorry everyone, the question was based on a mistake... The main method actually had a throws Exception
clause that I was missing. I've removed that and the code is now behaving as expected. Thanks for all the help!