Is it possible to assign the same value to multiple keys in a dict object at once?

Question

In Python, I need a dictionary object which looks like:

{'a': 10, 'b': 20, 'c': 10, 'd': 10, 'e': 20}

I've been able to get this successfully by combining the dict.update() and dict.fromkeys() functions like so:

myDict = {}
myDict.update(dict.fromkeys(['a', 'b', 'c'], 10))
myDict.update(dict.fromkeys(['b', 'e'], 20))

However, because the code is being written for novice users who may need to make add keys/values on occasion, I'd prefer a simple bare-bones (Perl-like) syntax such as:

myDict = {}
myDict['a', 'c', 'd'] = 10
myDict['b', 'e'] = 20

This, however, gives me:

myDict = {('a', 'c', 'd'): 10, ('b', 'e'): 20}

Is there a way I can simplify my first example (using dict.update() and dict.fromkeys()) further, and get the dict object I'm looking for?

Or, alternatively, if I have a dict with tuples as in my second example, is there an easy way for me to do a lookup such as myDict['c'] or myDict.get('c') and get the value 10?

Answer 1

I would say what you have is very simple, you could slightly improve it to be:

my_dict = dict.fromkeys(['a', 'b', 'c'], 10)
my_dict.update(dict.fromkeys(['b', 'e'], 20))

If your keys are tuple you could do:

>>> my_dict = {('a', 'c', 'd'): 10, ('b', 'e'): 20}
>>> next(v for k, v in my_dict.items() if 'c' in k)      # use .iteritems() python-2.x
10

This is, of course, will return first encountered value, key for which contains given element.

Answer 2

Your first example can be simplified using a loop:

myDict = {}
for key in ['a', 'c', 'd']:
    myDict[key] = 10
for key in ['b', 'e']:
    myDict[key] = 20

No specialized syntax or trickery, and I can't think of anything which would be easier to understand.

Regarding your second question, there is no simple and efficient way to do the lookup as in your second example. I can only think of iterating over the keys (tuples) and checking whether the key is in any of them, which isn't what you're looking for. Stick to using a straightforward dict with the keys you want.

In general, if you are aiming for code that can be understood by novices, stick to the basics such as if conditions and for/while loops.

Answer 3

Why not inherit from dict?

class LazyDict(dict):
    def keylist(self, keys, value):
        for key in keys:
            self[key] = value

>>> d = LazyDict()
>>> d.keylist(('a', 'b', 'c'), 10)
>>> d
{'a': 10, 'c': 10, 'b': 10}

but I prefer loop solution