If you want the largest sum of sequential numbers then something like this might work:
$cur = $max = 0;
foreach ($seq as $n)
{
$cur += $n;
if ($cur < 0) $cur = 0;
if ($cur > $max) $max = $cur;
}
That's just off the top of my head, but it seems right. (Ignoring that it assumes 0 is the answer for empty and all negative sets.)
Edit:
If you also want the sequence position:
$cur = $max = 0;
$cur_i = $max_i = 0;
$max_j = 1;
foreach ($seq as $i => $n)
{
$cur += $n;
if ($cur > $max)
{
$max = $cur;
if ($cur_i != $max_i)
{
$max_i = $cur_i;
$max_j = $max_i + 1;
}
else
{
$max_j = $i + 1;
}
}
if ($cur < 0)
{
$cur = 0;
$cur_i = $i + 1;
}
}
var_dump(array_slice($seq, $max_i, $max_j - $max_i), $max);
There might be a more concise way to do it. Again, it has the same assumptions (at least one positive integer). Also, it only finds the first biggest sequence.
Edit: changed it to use max_j
(exclusive) instead of max_len
.