Array not crossing 256 byte boundary

Question

Is it possible to create an array that doesn't cross 256 byte boundary? That is addresses of the individual array items only differ in the lower byte. This is weaker requirement than keeping the array aligned to 256 bytes. The only solution I could think of was aligning to next_power_of_two(sizeof(array)), but I'm not sure about the gaps that would appear this way.

It is for a library for AVR microcontrollers, and this would save me a few precious instructions in an interrupt handler.The array that should have this property is 54 byte long out of about 80 bytes of total static memory used by the library. I'm looking for a way that doesn't increase the memory requirements.

I'm using avr-as gnu assembler and avr-ld linker.

Example:If the array starts at address 0x00f0, then the higher word will change from 0x00 to 0x01 while traversing the array.

I don't really care whether it starts at address 0x0100 or 0x0101 as long as it doesn't cross the boundary.

Answer 1

You only need 64 byte alignment to meet this requirement, so e.g. this should work:

uint8_t a[54] __attribute__ ((aligned(64)));

Answer 2

I don't know anything about AVR microcontrollers, but, generally speaking, static variables are usually placed in the data section of the executable, and, since your static memory requirements are low, all you need to ensure is that the data section is 256 byte aligned. (Which it may be by default. On x86, it usually is.) Check the linker options...