How can Makefile print itself?

Question

It does not print itself.

$ cat Makefile 
files := $(foreach dir,.,$(wildcard $(dir)/*))


all:
         cat $(files)
$ make
cat 
a
a
b
b
^C%
$ ls -lsa .
total 20
4 drwxr-xr-x  3 tester  tester  512 Oct 20 15:01 .
4 drwxr-xr-x  3 tester  tester  512 Oct 20 14:19 ..
4 -rw-r--r--  1 tester  tester   69 Oct 20 15:01 Makefile
$ cat ./*
files := $(foreach dir,.,$(wildcard $(dir)/*))


all:
         cat $(files)

Answer 1

Why you would want to do this is beyond me but why not have your Makefile thus:

all:
    @cat Makefile

The code you have attempts to print every file in the directory, at least under GNU Make 3.81.

It appears, from your transcript, that your $(files) variable in the cat is expanding to nothing, which means you're just running cat on its own. I gather you typed in a and bb and they were echoed back by the cat before you broke out with CTRLC or equivalent.

I get the same effect when I change that first line to xfiles := ....

I would look into the documentation to ensure OBSD (your version) supports this foreach construct (and wildcard). If not, you'll have to find another way.