Finding the path of the program that will execute from the command line in Windows

Question

Say I have a program X.EXE installed in folder c:\abcd\happy\ on the system. The folder is on the system path. Now suppose there is another program on the system that's also called X.EXE but is installed in folder c:\windows\.

Is it possible to quickly find out from the command line that if I type in X.EXE which of the two X.EXE's will get launched? (but without having to dir search or look at the process details in Task Manager).

Maybe some sort of in-built command, or some program out there that can do something like this? :

detect_program_path X.EXE

Answer 1

Yes, use the where command. The first result in the list is the one that will execute.

C:\> where notepad
C:\Windows\System32\notepad.exe
C:\Windows\notepad.exe

According to this blog post, where.exe is included with Windows Server 2003 and later, so this should just work with Vista, Win 7, et al.

Answer 2

Here's a little cmd script you can copy-n-paste into a file named something like where.cmd:

@echo off
rem - search for the given file in the directories specified by the path, and display the first match
rem
rem    The main ideas for this script were taken from Raymond Chen's blog:
rem
rem         http://blogs.msdn.com/b/oldnewthing/archive/2005/01/20/357225.asp
rem
rem
rem - it'll be nice to at some point extend this so it won't stop on the first match. That'll
rem     help diagnose situations with a conflict of some sort.
rem

setlocal

rem - search the current directory as well as those in the path
set PATHLIST=.;%PATH%
set EXTLIST=%PATHEXT%

if not "%EXTLIST%" == "" goto :extlist_ok
set EXTLIST=.COM;.EXE;.BAT;.CMD;.VBS;.VBE;.JS;.JSE;.WSF;.WSH
:extlist_ok

rem - first look for the file as given (not adding extensions)
for %%i in (%1) do if NOT "%%~$PATHLIST:i"=="" echo %%~$PATHLIST:i

rem - now look for the file adding extensions from the EXTLIST
for %%e in (%EXTLIST%) do @for %%i in (%1%%e) do if NOT "%%~$PATHLIST:i"=="" echo %%~$PATHLIST:i