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754

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3

Hi,

I have a tcl script which 'exec' rpmbuild. When doing so, the 'topdir' used by rpmbuild is wrong. I have a .rpmmacros file in my home directory and if I call manually rpmbuild, it works fine, ie. the 'topdir' is not the default one.

I added a [exec rpmbuild "--showrc" ] in the tcl script to check the value of topdir and it says '-14: _topdir %{_usrsrc}/redhat' which is the default value.

Can someone explain me why is that situation and how to solve it ?

I would prefer not to have to specify it with --define because it is actually done in a makefile and I don't want to touch it (if no other choice, I will do it).

Thanks in advance

A: 

TCL will exec in the current directory by default. You can change the current directory by using the TCL command http://www.tcl.tk/man/tcl8.4/TclCmd/cd.htm cd, for example:

cd ~username

If topdir is an environment variable, you might be able to set it http://www.tcl.tk/man/tcl8.4/TclCmd/tclvars.htm#M4 like this:

set env(topdir) whatever/you/want
Joseph Bui
A: 

My first check would be to make sure you execute the same thing. Do these two on the command line to make sure aliases or paths do not disturb anything.

which rpmbuild

echo 'puts [auto_execok rpmbuild]' | tclsh
Hugge
+2  A: 

There's two ways to change the default rpmbuild topdir:

  1. Per-User: By configuring the RPM topdir in $HOME/.rpmmacros

    %_topdir    $HOME/rpmbuild
    
  2. Per-Project: By configuring the RPM topdir in the Makefile or on the command line

    rpmbuild --define '_topdir build' -ba package.spec
    

Note: in both cases, you will need to make sure your topdir directory has the appropriate directories (BUILD, SRPM, RPM, SPECS and SOURCES)

Zach Garner