views:

258

answers:

2
+1  A: 

Well, theoretically, if /lib was a symlink to /drive2/foo, then /lib/../lib would point to /drive2/lib if I'm not mistaken. Theoretically...

Edit: I just tested and it's not the case - it comes back to /lib. Hrm :(

Artem Russakovskii
+2  A: 

An attempt at an answer (which I gathered from a few minutes of looking at the gcc.c driver source and the Makefile environment).

These paths are constructed in runtime from:

  1. GCC exec prefix (see GCC documentation on GCC_EXEC_PREFIX)
  2. The $LIBRARY_PATH environment variable
  3. The $LPATH environment variable (which is treated like $LIBRARY_PATH)
  4. Any values passed to -B command-line switch
  5. Standard executable prefixes (as specified during compilation time)
  6. Tooldir prefix

The last one (tooldir prefix) is usually defined to be a relative path: From gcc's Makefile.in

# Directory in which the compiler finds libraries etc.
libsubdir = $(libdir)/gcc/$(target_noncanonical)/$(version)
# Directory in which the compiler finds executables
libexecsubdir = $(libexecdir)/gcc/$(target_noncanonical)/$(version)
# Used to produce a relative $(gcc_tooldir) in gcc.o
unlibsubdir = ../../..
....
# These go as compilation flags, so they define the tooldir base prefix
# as ../../../../, and the one of the library search prefixes as ../../../
# These get PREFIX appended, and then machine for which gcc is built
# i.e i484-linux-gnu, to get something like: 
# /usr/lib/gcc/i486-linux-gnu/4.2.3/../../../../i486-linux-gnu/lib/../lib/
DRIVER_DEFINES = \
-DSTANDARD_STARTFILE_PREFIX=\"$(unlibsubdir)/\" \
-DTOOLDIR_BASE_PREFIX=\"$(unlibsubdir)/../\" \

However, these are for compiler-version specific paths. Your examples are likely affected by the environment variables that I've listed above (LIBRARY_PATH, LPATH)

ASk
@ASk, I checked for LIBRARY_PATH and LPATH in the environment (bash), and neither is defined. Tracing the g++ source should be guaranteed to terminate with the resolution of this mystery; thanks for the clue.
Thomas L Holaday