OpenGL: projecting mouse click onto geometry

Question

I have this view set:

glMatrixMode(GL_MODELVIEW); //Switch to the drawing perspective
glLoadIdentity(); //Reset the drawing perspective

and I get a screen position (sx, sy) from a mouse click.

Given a value of z, how can I calculate x and y in 3d-space from sx and sy?

Answer 1

libqglviewer has a good selection framework if that's what you're looking for

Answer 2

This is actually dependent on the projection matrix, not the model-view matrix. http://www.toymaker.info/Games/html/picking.html should help you out -- it's D3D-centric but the theory is the same.

If you're looking to do mouse-based picking, though, I suggest using the selection rendering mode.

Edit: Mind you, the model-view matrix does come into play, but since yours is identity it's a nonissue.

Answer 3

This is best answered by the most authoritative source, OpenGL's web site.

Answer 4

You should use gluUnProject:

First, compute the "unprojection" to the near plane:

GLdouble modelMatrix[16];
GLdouble projMatrix[16];
GLint viewport[4];

glGetIntegerv(GL_VIEWPORT, viewport);
glGetDoublev(GL_MODELVIEW_MATRIX, modelMatrix);
glGetDoublev(GL_PROJECTION_MATRIX, projMatrix);

GLdouble x, y, z;
gluUnProject(sx, viewport[1] + viewport[3] - sy, 0, modelMatrix, projMatrix, viewport, &x, &y, &z);

and then to the far plane:

// replace the above gluUnProject call with
gluUnProject(sx, viewport[1] + viewport[3] - sy, 1, modelMatrix, projMatrix, viewport, &x, &y, &z);

Now you've got a line in world coordinates that traces out all possible points you could have been clicking on. So now you just need to interpolate: suppose you're given the z-coordinate:

GLfloat nearv[3], farv[3];  // already computed as above

if(nearv[2] == farv[2])     // this means we have no solutions
   return;

GLfloat t = (nearv[2] - z) / (nearv[2] - farv[2]);

// so here are the desired (x, y) coordinates
GLfloat x = nearv[0] + (farv[0] - nearv[0]) * t,
        y = nearv[1] + (farv[1] - nearv[1]) * t;