Ok I've found with 3 different scripts ^^
in the java code, for each function :
long time1 = System.currentTimeMillis();
// some code for function 1
long time2 = System.currentTimeMillis();
try {
OutputStreamWriter osw = new OutputStreamWriter(new FileOutputStream(new File("log.txt"),true));
osw.write("function1,"+(time2 - time1)+"\n");
osw.close();
} catch (FileNotFoundException ex) {
ex.printStackTrace();
} catch (IOException ex) {
ex.printStackTrace();
}
a bash code to run the 500 times the two algorithms
#!/bin/bash
i=0
while [ $i -lt 500 ]
do
./algo1.ex
./algo2.ex
i=$(( $i+1 ))
done
an (or two actually, one for each algorithm) expect code to do the command during the execution
#!/usr/bin/expect -f
spawn java -jar algo1.jar
expect "enter your choice" {send "1\n"}
expect "enter a name :" {send "Peju, M.\n"}
expect "enter your choice" {send "2\n"}
expect "enter a name :" {send "Creasy, R. J.\n"}
expect "enter your choice" {send "0\n"}
exit
As I didn't know how to do it in bash, to count I used a python code
#!/usr/bin/python
# -*- coding: utf8 -*-
import sys
if __name__ == "__main__":
if sys.argv[1:]:
arg = sys.argv[1]
filin = open(arg, 'r')
line = filin.readline()
res= 0, 0, 0
int n = 1
while line !='':
t = line.partition(',')
if t[0] == "function1":
res = (res[0] + int(t[2]), res[1], res[2])
if t[0] == "function2":
res = (res[0], res[1] + int(t[2]), res[2])
if t[0] == "function3":
res = (res[0], res[1], res[2] + int(t[2]))
ligne = filin.readline()
n = n+1
print res
print (res[0]/(n/3.0), res[1]/(n/3.0), res[2]/(n/3.0))
filin.close()
and it works
but thanks for your propositions