Is there any runtime cost for Casting in Java?

Question

Would there be any performance differences between these two chunks?

public void doSomething(Supertype input)
{
    Subtype foo = (Subtype)input;
    foo.methodA();
    foo.methodB();
}

vs.

public void doSomething(Supertype input)
{
    ((Subtype)input).methodA();
    ((Subtype)input).methodB();
}

Any other considerations or recommendations between these two?

Answer 1

Acording to this article, there is a cost associated with casting: http://www.javaworld.com/javaworld/jw-12-1999/jw-12-performance.html

Answer 2

Well, the compiled code probably includes the cast twice in the second case - so in theory it's doing the same work twice. However, it's very possible that a smart JIT will work out that you're doing the same cast on the same value, so it can cache the result. But it is having to do work at least once - after all, it needs to make a decision as to whether to allow the cast to succeed, or throw an exception.

As ever, you should test and profile your code if you care about the performance - but I'd personally use the first form anyway, just because it looks more readable to me.

Answer 3

Yes. Checks must be done with each cast along with the actual mechanism of casting, so casting multiple times will cost more than casting once. However, that's the type of thing that the compiler would likely optimize away. It can clearly see that input hasn't changed its type since the last cast and should be able to avoid multiple casts - or at least avoid some of the casting checks.

In any case, if you're really that worried about efficiency, I'd wonder whether Java is the language that you should be using.

Personally, I'd say to use the first one. Not only is it more readable, but it makes it easier to change the type later. You'll only have to change it in one place instead of every time that you call a function on that variable.

Answer 4

In the first case :

Subtype foo = (Subtype)input;

it is determined at compile time, so no cost at runtime.

In the second case :

((Subtype)input).methodA();

it is determined at run time because compiler will not know. The jvm has to check if it can converted to a reference of Subtype and if not throw ClassCastException etc. So there will be some cost.