This is somewhat hard to describe, so bare with me. Essentially I have a triangle in 3D space defined by its 3 vertices, p0, p1, and p2.
I wish to calculate a plane in this 3D space which lies along both p0 and p1 and faces a third point, p2.
This plane is to be defined by a position and normalised direction/
In addition to lying along p0 and p1, and facing p2, the plane should also be perpendicular to the plane created by p0, p1, and p2
I've struggled with this for quite a while and any help anyone can offer is greatly appreciated.