This description is valid for Linux 32 bit: When a Linux program begins, all pointers to command-line arguments are stored on the stack. The number of arguments is stored at 0(%ebp), the name of the program is stored at 4(%ebp), and the arguments are stored from 8(%ebp).
I need the same information for 64 bit.
Edit: I have working code sample which shows how to use argc, argv[0] and argv[1]: http://cubbi.com/fibonacci/asm.html
.globl _start
_start:
popq %rcx # this is argc, must be 2 for one argument
cmpq $2,%rcx
jne usage_exit
addq $8,%rsp # skip argv[0]
popq %rsi # get argv[1]
call ...
...
}
It looks like parameters are on the stack. Since this code is not clear, I ask this question. My guess that I can keep rsp in rbp, and then access these parameters using 0(%rbp), 8(%rbp), 16(%rbp) etc. It this correct?