views:

295

answers:

4

The following snippet draws a gray square.

glColor3b(50, 50, 50);

glBegin(GL_QUADS);
glVertex3f(-1.0, +1.0, 0.0); // top left
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();

In my application, behind this single square exists a colored cube.

What function should I use to make square (and only this square) opaque?

+2  A: 

glColor4f(float r,float g, float b, flaot alpha);
(in your case maybe clColor4b)
also make sure, that blending is enabled.
(you have to reset the color to non-alpha afterwads, which might involve a glGet* to save the old vertexcolor)

qwerty
+2  A: 

Use glColor4 instead of glColor3. For example:

glBlendFunc(GL_SRC_ALPHA,GL_ONE);
glColor4f(1.0f,1.0f,1.0f,0.5f);
DNS
Thanks. Hmm, doesn't seem to be working for me, what could I be doing wrong?
nbolton
+2  A: 

You can set colors per vertex

glBegin(GL_QUADS);
glColor4f(1.0, 0.0, 0.0, 0.5); // red, 50% alpha
glVertex3f(-1.0, +1.0, 0.0); // top left
// Make sure to set the color back since the color state persists
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();
basszero
+2  A: 

In the init function, use these two lines:

glEnable(GL_BLEND);
glBlendFunc(GL_SRC_ALPHA, GL_ONE_MINUS_SRC_ALPHA);

And in your render function, ensure that glColor4f is used instead of glColor3f, and set the 4th argument to the level of opacity required.

glColor4f(1.0, 1.0, 1.0, 0.5);

glBegin(GL_QUADS);
glVertex3f(-1.0, +1.0, 0.0); // top left
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();
nbolton