In C89, floor() returns a double. Is the following guaranteed to work? double d = floor(3.0 + 0.5); int x = (int) d; assert(x == 3); My concern is that the result of floor might not be exactly representable in IEEE 754. So d gets something like 2.99999, and x ends up being 2. For the answer to this question to be yes, all integers ...
I'd like a floor function with the syntax int floor(double x); but std::floor returns a double. Is static_cast <int> (std::floor(x)); guaranteed to give me the correct integer, or could I have an off-by-one problem? It seems to work, but I'd like to know for sure. For bonus points, why the heck does std::floor return a double in t...
What is a good algorithm to determine the necessary fraction needed to add/sub to the number in order to round it to the nearest integer without using the inbuilt ceiling or floor funcitons? Edit: Looking for a mathematical number trick to figure out the part needed to round the number to the nearest integer. The more primitive the mat...
I have floor(sqrt(floor(x))). Which is true: The inner floor is redundant. The outer floor is redundant. ...
I am pulling timestamps from a file that I want to create a new DateTime for, but I want to create the DateTime at the floor of the hour (or any Joda Period will do). How Can I do this? ...
Hi All, I need to get the left hand side integer value from a decimal or double. For Ex: I need to get the value 4 from 4.6. I tried using Math.Floor function but it's returning a double value, for ex: It's returning 4.0 from 4.6. The MSDN documentation says that it returns an integer value. Am I missing something here? Or is there a dif...
I need to mimic the exact functionality of the ceil(), floor() and round() functions on bcmath numbers, I've already found a very similar question but unfortunately the answer provided isn't good enough for me since it lacks support for negative numbers and the precision argument for the round() function is missing. I was wondering if a...
The // "integer division" operator of Python surprised me, today: >>> math.floor(11/1.1) 10.0 >>> 11//1.1 9.0 The documentation reads "(floored) quotient of x and y". So, why is math.floor(11/1.1) equal to 10, but 11//1.1 equal to 9? ...
I am working on a piece of code where I need to deal with uvs (2D texture coordinates) that are not necessarily in the 0 to 1 range. As an example, sometimes I will get a uv with a u component that is 1.2. In order to handle this I am implementing a wrapping which causes tiling by doing the following: u -= floor(u) v -= floor(v) Doing...
I cannot understand why this throws undefined reference to `floor'": double curr_time = (double)time(NULL); return floor(curr_time); Hasn't it been casted to double, which is what floor receives? ...
I need to round times down to the nearest quarter hour in PHP. The times are being pulled from a MySQL database from a datetime column and formatted like 2010-03-18 10:50:00. Example: 10:50 needs to be 10:45 1:12 needs to be 1:00 3:28 needs to be 3:15 etc. I'm assuming floor() is involved but not sure how to go about it. Thanks ...
The cod that I am using contains these snippets of code. I am calling ThetaG_JD with the argument 2455343.50000 which is just a sample Julian date. Every time I run the program, I receive a EXC_BAD_ACCESS on the indicated line. When using gdb and printing out the intermediary values and passing them through the floor function, I get no e...
Hi, I'm fetching a datetime from MYSQL which looks like: 2010-08-11 11:18:28 I need to convert it into the "floor" or the earliest 15 minute interval and output in milliseconds for another function. So, this case would be: 2010-08-11 11:15:00 in milliseconds Whoops! Sorry - need to clarify - I need code that will transform it int...
I need to do the following equation floor(e%100000) where e is a double. I know mod only accepts int values, how do I go about achieving this same result? Thanks ...
How to display a value as follows in oracle: 99.99 as 99.9900, 99.9 as 99.9000, 9.99 as 9.9900, 99 as 99.0000 All cases should be satisfied.. Please help... ...