What does the ',' operator do in C?
What does the ',' operator do in C? ...
What does the ',' operator do in C? ...
Can anyone tell me what this cast has for effect (besides setting happyNumber to 1337), if any at all, and if it has no other effect, how come I can write code like this??? Is this a compiler bug, or some "hidden away feature" of C++? int happyNumber = static_cast<int>(123.456, TRUE, "WTF" , false , "IS" , NULL , "GOING" , 0xff , "ON???...
Hello all, I have a simple question that I am posing mostly for my curiousity. What are the differences between these two lines of code? (in C++) for(int i = 0; i < N, N > 0; i++) for(int i = 0; i < N && N > 0; i++) The selection of the conditions is completely arbitrary, I'm just interested in the differences between , and &&. I'm...
Why is the expression specified inside a comma operator (such as the example below) not considered a constant expression? For example, int a = (10,20) ; when given in global scope yields an error "initializer is not a constant", though both the expressions separated by a comma operator are constants (constant expressions). Why is th...
Hi, I'm trying to overload the comma operator with a non-friend non-member function like this: #include <iostream> using std::cout; using std::endl; class comma_op { int val; public: void operator,(const float &rhs) { cout << this->val << ", " << rhs << endl; } }; void operator,(const float &lhs, const comma_o...
Today, I found out that you can write such code in C++ and compile it: int* ptr = new int(5, 6); What is the purpose of this? I know of course the dynamic new int(5) thing, but here i'm lost. Any clues? ...
is it possible to construct variadic arguments for function by overloading operator comma of the argument? i want to see an example how to do so.., maybe something like this: template <typename T> class ArgList { public: ArgList(const T& a); ArgList<T>& operator,(const T& a,const T& b); } //declaration void myFunction(ArgList<in...
the second function gives error C2803 http://msdn.microsoft.com/en-us/library/zy7kx46x%28VS.80%29.aspx : 'operator ,' must have at least one formal parameter of class type. any clue? template<class T,class A = std::allocator<T>> class Sequence : public std::vector<T,A> { public: Sequence<T,A>& operator,(const T& a) { this-...
Hello, I have been programming in C and C++ for a few years and now I'm just now taking a college course in it and our book had a function like this for an example int foo(){ int x=0; int y=20; return x,y; //y is always returned } I have never seen such syntax. In fact, I have never seen the , operator used outside of parameter ...
If you see this code, class A{ public: A(int a):var(a){} int var; }; int f(A obj) { return obj.var; } int main() { //std::cout<<f(23); // output: 23 std::cout<<f(23, 23); // error: too many arguments to function 'int f(A)' return 0; } f(23, 23) does not compile because the comma acts as a separator here a...
Why is the following line producing errors? for(int i = 0, int pos = 0, int next_pos = 0; i < 3; i++, pos = next_pos + 1) { // … } error: expected unqualified-id before ‘int’ error: ‘pos’ was not declared in this scope error: ‘next_pos’ was not declared in this scope Compiler is g++. ...