what are function pointers
Possible Duplicate: What is the point of function pointers? can anyone explain what function pointers are and why they are needed in layman terms. In c context please? ...
Possible Duplicate: What is the point of function pointers? can anyone explain what function pointers are and why they are needed in layman terms. In c context please? ...
I have code that looks like this: extern "C" __declspec(dllexport) myInterface(int id, void** pFunction) { ... } I need to make the void** pFunction argument point to a function so that the caller can use this function via the pFunction pointer. This function gets called through a DLL, I don't want to do it this way but for a lot ...
I'm building a series of predicates that duplicate lots of code, and so are being changed into a single template function class based on the std::unary_function. The idea is that my class interface requires methods such as Element_t Element() and std::string Name() to be defined, so the predicate template arguments are the object type an...
It's hackish, I know, but I recently needed to implement a stream class which would act mostly like a standard stream, but which would detect the std::endl manipulator and special-case it's behaviour. My first attempt at a particular method implementation was... mystream& mystream::operator<< (std::basic_ostream<char>& (*p) (std::basic_...
I am trying to create a function in VC++ that takes a function pointer but I keep getting syntax errors. The declaration in my header file looks like this: void ApplyFuncToCellsInSelection(void(*func)(CPoint, *CSpreadWnd)); Here is the definition: void CSpreadWnd::ApplyFuncToCellsInSelection(void(*func)(CPoint, *CSpreadWnd)) { ... ...
Is this correct? int (*(*ptr)())[]; I know this is trivial, but I was looking at an old test about these kind of constructs, and this particular combination wasn't on the test and it's really driving me crazy; I just have to make sure. Is there a clear and solid understandable rule to these kind of declarations? (ie: pointer to... arr...
I was found general member function pointer call method. buf that example is only void type. I want to make general return type of method function call. class Callback { public: void operator()() { call(); }; virtual void call() = 0; }; class BasicCallback : public Callback { // pointer to member function void (*func...
Hi there, I'm stuck with a weird problem. I have two files a.c and b.c as follows: b.c: #include <stdlib.h> int *foo() { int *x; x = (int *) malloc(sizeof(int)); *x = 4; return x; } I compile b.c to b.so using gcc: $ gcc -o b.so -shared -fpic a.c: #include <stdio.h> #include <dlfcn.h> int main() { void *hdl; hdl = dlop...
what is wrong with the following code? parseCounter1() and parseCounter1() below are two functions. I put their pointers in const OptionValueStruct so that they can be called accordingly when each element of option_values[] are gone through: typedef struct OptionValueStruct{ char counter_name[OPTION_LINE_SIZE]; int* counter_...
How can I use a static function pointer member in my class template? I'm working with C++ in Visual Studio, and my code looks similar to the following: template<typename T> class ClassTemplate { public: static T* CallIt() { return ClassTemplate<T>::mFunctionPointer(); } private: static T* (*mFunctionPointer)(); }; When I com...
I can have a typedef function pointer in a class like this: template<typename T> class MyClass { public: typedef T (*fptr)(T); void doSomething(fptr my_fptr) { /*...*/ } }; and this works fine. but if I inherit from such a class, as below: template<typename T> class MyClass { public: typedef T (*fptr)(T); virtual void doSo...
Maybe is a silly questiion, but I haven't found a solution to what I want. Basically, I would like to declare a pointer to an array of pointers to function pointers to functions with N parameters that returns an const pointer to an int. The code below is declaring an array of pointers to the function pointers: int *const (**fptr[10])...
Hi, With respect to this question, we can declare a function that returns pointer to array as: int (*function())[3] which returns Ax3 array, ok. How is the proper way to declare a function pointer that points this kind of function? ...
I currently have a mapping setup to convert from one base class to another base class. I am mapping a customer class to a thrid party control. The values are similiar but there is enough differences that I can't reuse the thrid party control. _converters = new Dictionary<Type, Func<AnnotationBase, AnnotationMark>>(); _converters.Add( ty...
Setting: A pseudo-random pattern has to be generated. There are several ways / or algorithms availible to create different content. All algorithms will generate a list of chars (but could be anything else)... the important part is, that all of them return the same type of values, and need the same type of input arguments. It has to be p...
I have a program that calls a function in a dynamically-linked library. All of the function calls work fine, except one. double *frameData = NULL; int frameDataSize = 0; g_BeamGage_GetSingleFrame(BEAMGAGE_ID, &frameData, &frameDataSize); //error here When BeamGage_GetSingleFrame is called when debugging my program, I get a runtime err...
i basically want to use a dif function to extract a different element of a class (ac). the code is similar to this: .h: class MyClass { public: double f1(AnotherClass &); void MyClass::f0(AnotherClass & ac, double(MyClass::*f1)(AnotherClass &)); }; .cc: double MyClass::f1(AnotherClass & ac) { return ac.value; } void M...
In Bjarne Stroustrup's home page (C++0x FAQ): struct X { int foo(int); }; std::function<int(X*, int)> f; f = &X::foo; //pointer to member X x; int v = f(&x, 5); //call X::foo() for x with 5 How it works? How std::function calls foo member function? According to the template parameter int(X*, int), is &X::foo converted from the memb...
Is it possible to use boost::fusion::invoke function to call a function that has default arguments without specifying those? Example: void foo(int x, int y = 1, int z = 2) { std::cout << "The sum is: " << (x + y + z) << std::endl; } ... // This should call foo(0). It doesn't work because the type of foo is void (*) (int, int, int)....
Say I have a function f(a, b, c). Is it possible to create function pointers g and h such that when you use g and h they use a predetermined value for one of the arguments? For example (*g)(b, c) would be equivalent to f(1, b, c) and (*h)(b, c) would be equivalent to calling f(2, b, c). The reason why I am doing this is that I am calli...